0.0825t^2-0.896t+1.759=0

Solution for 0.0825t^2-0.896t+1.759=0 equation:

0.0825t^2-0.896t+1.759=0

a = 0.0825; b = -0.896; c = +1.759;
Δ = b2-4ac
Δ = -0.8962-4·0.0825·1.759
Δ = 0.222346
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.896)-\sqrt{0.222346}}{2*0.0825}=\frac{0.896-\sqrt{0.222346}}{0.165}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.896)+\sqrt{0.222346}}{2*0.0825}=\frac{0.896+\sqrt{0.222346}}{0.165}
$